题目链接:700. 二叉搜索树中的搜索
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def searchBST(self, root: TreeNode, val: int) -> Optional[TreeNode]:
if root is None:
return None
if root.val == val:
return root
elif root.val > val:
return self.searchBST(root.left, val)
else:
return self.searchBST(root.right, val)