题目链接:965. 单值二叉树
遍历二叉树判断。
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def isUnivalTree(self, root: TreeNode) -> bool:
if root is None:
return True
if root.left is not None and root.val != root.left.val:
return False
if root.right is not None and root.val != root.right.val:
return False
if not self.isUnivalTree(root.left) or not self.isUnivalTree(root.right):
return False
return True